Для чего предназначена система mathcad
I’m trying to buy Mathcad for use in the classes I teach. PTC seems to have handed off their online sales to a company called Digital River, but the web site also directs me to a sales rep who works for a company called EAC Product Development Solutions. She offered to sell me a 1 year license for $295 when the online price is $56.
I don’t understand what’s going on. Is this the same version?
I just got off the phone with the rep at EAC (who was professional and helpful, BTW) and she couldn’t explain what PTC was doing, but is trying to get me an answer. She did say that she gets lots of complaints about how hard it is to deal with PTC. Ugh.
Can anyone in the community enlighten me? It seems like PTC has decided to outsource their sales, but has sent it to two different companies who don’t talk to each other and have different pricing. Can this be right? I have to be missing something.
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14 REPLIES 14
LucMeekes
23-Emerald III
May 30, 2019 11:23 AM
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May 30, 2019 11:23 AM
If you use it to teach in classes. Do you really need all the features that Prime offers? If not, consider to use the free Express edition of Prime. It really is free, and your students can install it on their home PC’s as well.
I guess you’ve read the stories of support and maintenance and (lack of) development by PTC regarding Prime: why would you pay?
PTC changed their way of doing business regarding Prime in that they supposedly now only sell yearly subscriptions. BTW $295 or $56 seems like a bargain. This link
will sell an individual license for €625 (about $700 or more?).
mfrench
12-Amethyst
May 30, 2019 11:45 AM
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May 30, 2019 11:45 AM
I thought about having them use Express, but it’s missing a lot of features. The full feature set only lasts for 30 days and $56 is a pretty reasonable price for Mathcad.
I’ve just gotten off the phone with the sales rep from EAC Product Development Solutions and she figured out how to match the online student price. The best part, is that I got to talk with a friendly, well-informed person who solved my problem.
If anyone at a school or university wants to buy Mathcad, I recommend contacting:
Education Account Manager
EAC Product Development Solutions
1-888-225-7579 x 118
LucMeekes
23-Emerald III
May 30, 2019 11:49 AM
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May 30, 2019 11:49 AM
For that price, do you get Mathcad 15 along?
And is it a per year subscription?
mfrench
12-Amethyst
May 31, 2019 07:29 AM
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May 31, 2019 07:29 AM
The Prime license has always included a V15 license so files can be converted. I didn’t ask specifically, but I assume this one will as well.
Yes, that’s a 1 year subscription. Apparently, PTC has moved to subscriptions only.
terryhendicott
May 30, 2019 11:42 PM
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May 30, 2019 11:42 PM
I suggest you keep searching and asking questions. From ptc site:-
Mathcad Student Downloads
PTC Mathcad is the industry’s standard for engineering calculation software, enabling you to solve your most complex problems, and share your calculations with colleagues. To prepare students for the work- force, PTC Academic is committed to providing access to Mathcad for free.
LucMeekes
23-Emerald III
May 31, 2019 02:33 AM
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May 31, 2019 02:33 AM
Then, if you click further to the Academic or K12 buttons, its an offer for Express.
And the link to FIRST is an offer for Prime 3.1.
mfrench
12-Amethyst
May 31, 2019 07:34 AM
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May 31, 2019 07:34 AM
I noticed these weird links on their web site. They are not the only ones, either. It almost looks like they posted an alpha build of this part of their web site and then never looked at it again. I had a hard time finding the page for the student version of Mathcad and may not have kept looking had I not already known it was there.
No worries though, EAC is much easier to deal with and seems to have solved the problem for me.
Thanks to the community for your help
mfrench
12-Amethyst
Jul 03, 2019 12:05 PM
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Jul 03, 2019 12:05 PM
I just checked back and saw your note. I do know about Mathcad Express and it’s helpful. However, the free license only lasts 30 days, so my students need to buy Mathcad since a semester us 16 weeks. Fair enough. My concern is that navigating PTCs web site and figuring out how to buy Mathcad is surprisingly difficult. The system seems to be set up for corporate or organizational purchases.
Perhaps my current experience will help illustrate. I bought a student license through EAC (who I found using a link on the PTC web site) and the instructions for install don’t work because the customer number on the Order Fulfillment Letter doesn’t match the one on my account.
I responded to PTC with a request for assistance and they emailed me back, asking me for a copy of the Order Fulfillment Letter — the one they sent me. I also contacted EAC, who sent me a different set of instructions for logging in and downloading a license. Those instructions don’t work because I don’t have a global support agreement. I have a site number, a customer number and a sales order number, but apparently that’s not enough.
The details in this case probably aren’t that important. I’ll go through a couple more cycles with PTC and EAC and will eventually get it working. My students report the same kinds of problems.
Werner_E
Jul 03, 2019 01:21 PM
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Jul 03, 2019 01:21 PM
I agree that PTC sure is a company you don’t want to have to deal with voluntarily. Getting help with simple things like downloading a software or installing it and get it to run can be quite nerve-racking until you find out the appropriate contact data. PTC doesn’t make it easy for customers, thats a fact.
Concerning Prime Express you have to be aware that its a free lifetime license!
Its just that during the first 30 days the program acts as a full version and after that period it falls back to a limited version you still can use for basic tasks or to view worksheets made with the full version.
But you will lose advanced features and functions like programming, solve blocks, symbolics, etc.
This is different to the evaluation version of Mathcad 15 as this version will stop working completely after the trial period.
VladimirN
Aug 23, 2019 05:07 AM
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Aug 23, 2019 05:07 AM
You can find PTC’s software reseller in your local region here: https://www.ptc.com/en/partners/find-your-partner
mfrench
12-Amethyst
Aug 23, 2019 07:30 AM
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Aug 23, 2019 07:30 AM
Thanks for the link. I’m already working with EAC Product Development Solutions, one of the vendors on their list. The good news is that the price for a 1 year student license is down to $50. This is a great move by PTC.
The semester has started, so I’ll know soon whether my students are having trouble buying Mathcad. Hopefully, we’re past most of the problems. Funny that we don’t have to go through this convoluted process to get MATLAB.
In other news, my university went to Windows 10 over the summer. For some reason, Mathcad disappeared from all the computers in my classroom when that happened. No more Mathcad in the classroom for me, I guess. Too bad.
Fred_Kohlhepp
23-Emerald I
Aug 23, 2019 08:23 AM
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Aug 23, 2019 08:23 AM
@mfrench wrote:
The good news is that the price for a 1 year student license is down to $50. This is a great move by PTC.
The semester has started, so I’ll know soon whether my students are having trouble buying Mathcad. Hopefully, we’re past most of the problems. Funny that we don’t have to go through this convoluted process to get MATLAB.
MATLAB used to be free to students. That’s why all the new engineers demanded MATLAB on their computers and didn’t have a clue about Mathcad when I brought it up; a great marketing ploy that I could never get MathSoft to understand (let alone PTC.)
In other news, my university went to Windows 10 over the summer. For some reason, Mathcad disappeared from all the computers in my classroom when that happened. No more Mathcad in the classroom for me, I guess. Too bad.
Mathcad runs fine on Windows 10. Maybe somebody at your school is trying to show you the future,
mfrench
12-Amethyst
Aug 23, 2019 08:34 AM
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Aug 23, 2019 08:34 AM
I suspect a license ran out and nobody wanted to pay to renew it, though I don’t know for sure. I’m running V15 on Windows 10 and haven’t had a problem.
mfrench
12-Amethyst
Apr 27, 2023 10:32 AM
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Apr 27, 2023 10:32 AM
Since people are still apparently reading this older post, perhaps an update would be helpful. My direct dealings with PTC are still frustrating. I generally get lost in the vortex of subscription numbers, customers numbers and sales order numbers. PTC often doesn’t understand that I bought a license for my two computers and usually mixes me up with other larger licenses at my university. I have even had to send them the renewal confirmations they originally sent me when they didn’t believe the ID numbers I gave them.
I still get all my licenses through Elizabeth Hall at EAC Product Development Solutions, a distributer for PTC. She and the tech support guy, Blaine, are just great. I recommend them to anyone looking for a stress-free way to get Mathcad Prime. Her email is ehall@eacpds.com
Since my original post, PTC has decided not allow EAC (and, I assume, other vendors) to see information related to student and professor licenses. It has made the license renewal process more difficult for me without any obvious benefit.
I have no idea why buying from PTC is like it is. My best guess is that they mostly want to deal with large customers who will send them purchase orders for large numbers of licenses and large support contracts. I feel like I’m an annoyance to them. I don’t know if that’s what they intend, but I still dread having to deal with them directly.
As always, I love Mathcad, but wish I could buy it from someone else.
TLDR: Mathcad Prime — Good. PTC — Ugh
Для чего предназначена система mathcad
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MathCAD Units Help
ptc-4992678
Mar 04, 2013 03:02 PM
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Mar 04, 2013 03:02 PM
MathCAD Units Help
I am using MathCAD Prime 2.0 for design calculations for a building I am engineering. I am fairly new to MathCAD, only learning a little about it in college. However, I am running into a units issue when calculating pounds per linear foot (lb/ft) to just pounds (a point load). I am taking 480 PLF * 4 ft, the feet should cancel out and you are left with just pounds. MathCAD is spitting out a lb*f, like the units for a moment. When I go to change the units to just pounds then it changes my units to (ft/s^2)*lb? Please explain to me what is going wrong here. See below for a screen shot:
Please note that the answer is correct, 1920 pounds is the right answer. Just the wrong units.
Thank you in advance,
Jon Recknagel | Structural Designer
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ptc-4992678
Mar 04, 2013 03:22 PM
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Mar 04, 2013 03:22 PM
I just answered my own question. A «lbf»= a pound force. It seems like they could have just left it at «lb» we are all aware that pounds is a force. Just my opinon I guess. Thanks anyway.
20 REPLIES 20
ptc-4992678
Mar 04, 2013 03:22 PM
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Mar 04, 2013 03:22 PM
I just answered my own question. A «lbf»= a pound force. It seems like they could have just left it at «lb» we are all aware that pounds is a force. Just my opinon I guess. Thanks anyway.
RichardJ
19-Tanzanite
Mar 04, 2013 03:58 PM
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Mar 04, 2013 03:58 PM
It seems like they could have just left it at «lb» we are all aware that pounds is a force.
The pound is a unit of mass, not force.
ptc-4992678
Mar 04, 2013 04:02 PM
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Mar 04, 2013 04:02 PM
I would disagree. Pounds (lb) is not a mass. Pounds is a force. F=mg, due to gravity.
RichardJ
19-Tanzanite
Mar 04, 2013 04:15 PM
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Mar 04, 2013 04:15 PM
What unit are you using for m?
ptc-4992678
Mar 04, 2013 04:28 PM
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Mar 04, 2013 04:28 PM
m=F/G, most engineering firms (in the US anyway) do not work in terms of metric units of mass. Everything is in pounds, a force. When you step on the scale at home you do not read your weight in terms of mass, you read your weight it terms of pounds, due to gravity, which is a force.
RichardJ
19-Tanzanite
Mar 04, 2013 04:49 PM
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Mar 04, 2013 04:49 PM
It’s not a question of metric vs non-metric. I asked because the only unit systems in which pounds are a force are the gravitational systems, in which the base units are force, length, and time, rather than mass length and time. If the base unit of force is the pound, then the mass unit is the slug, and is defined in terms of the pound. The slug is defined as a mass that accelerates by 1 ft/s2 when a force of one pound is applied.
All unit systems in Mathcad are based on mass, length and time though. It does not have unit systems based on either force, length and time as the base units, or weight, length, time as the base units. In Mathcad a pound is always a mass. A pound force is distinguished from that by using the nomenclature lbf.
What a bathroom scale says is irrelevant. Most people don’t even know the distinction between mass and weight. You can get scales that read kg too, and there is no unit system in which kg is a unit of anything other than mass.
MS_8437498
Nov 12, 2020 07:01 PM
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Nov 12, 2020 07:01 PM
«lbf» is a unit of force.
In the English unit the correct mass is a slug but no body uses the unit.
Fred_Kohlhepp
23-Emerald I
Nov 13, 2020 05:23 AM
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Nov 13, 2020 05:23 AM
You are absolutely correct!
lbf is pound force. lb (or lbm) is mass, so is slug.
SL_9674672
5-Regular Member
Nov 13, 2020 01:52 PM
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Nov 13, 2020 01:52 PM
Yep. Mathcad allows definition of lbm and lbf, for pounds of mass and pounds of force. I use these everyday when doing refrigeration work. Values for enthalpy (in the I-P system) are in BTU/lbm, but I also have to convert to psi for pipe pressure loss calculations. The gravitational constant is the method I use of converting from one to the other. The gravitational constant can be expressed as g_c = 32.174 ft*lbm/lbf*s..Use this in a calculation of the Generalized Energy Equations (derived from the Bernoulli equation) and it will allow use of pressure in psi and pounds of mass in the same equation. Also, the gravitational constant is equal to zero, so anything can be multiplied by it.
Fred_Kohlhepp
23-Emerald I
Nov 16, 2020 08:13 AM
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Nov 16, 2020 08:13 AM
I thought there was something wrong here!
SL_9674672
5-Regular Member
Nov 16, 2020 10:58 AM
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Nov 16, 2020 10:58 AM
Reference this paper; Piping-System Solutions Using Mathcad, B.K, Hodge and Robert P. Taylor, May 1, 2002. Without the use of g_c, this methodology won’t work in Mathcad and would require iterative hand solutions. Close enough is better than by hand. Also, you are likely seeing an error from defining g_c to only 3 decimal places. Extend your allowable decimal places to 12 for the definition of g, then use that to define g_c and it will be nearer to zero. Later today I should be able to post an actual example, gotta do some software maintenance first.
Fred_Kohlhepp
23-Emerald I
Nov 18, 2020 10:24 AM
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Nov 18, 2020 10:24 AM
Okay, attached (in Prime 4 Express) is a start through the paper Piping-System Solutions Using Mathcad, B.K, Hodge and Robert P. Taylor, May 1, 2002.
By doing a unit balance of equation (1), we can correct the equation and demonstrate that the conversion factor is NOT required.
piping systems2.mcdx
FDS
12-Amethyst
Nov 18, 2020 10:58 AM
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Nov 18, 2020 10:58 AM
Dear Fred, could you attach also a pdf? Thank you so much. Filip
Fred_Kohlhepp
23-Emerald I
Nov 18, 2020 11:08 AM
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Nov 18, 2020 11:08 AM
Original paper an mathcad file pdf attached
SL_9674672
5-Regular Member
Dec 07, 2020 01:16 PM
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Dec 07, 2020 01:16 PM
I really have to talk to our IT guys and find out why I can’t post a file. On the second page, W.s = g/g.c * z.a, The gravity term is not needed. That is why the result has an additional acceleration. The g.c is needed so the Ws comes out in feet. The equation is in terms of feet, especially when related to a hydronic system. Perhaps it is not required, but conversion to a pressure system vs. a pressure related to column height, is not really required. But when I analyze a refrigeration system, I am looking at flow rates in pounds of mass. Converting these flow rates to equivalent pressure losses is absolutely required. Also, all unit conversions are essentially multiplication by 1. They are never necessary but always helpful. Never required but performed constantly. When using IP units, conversion factors are absolutely necessary, unless we want to brush to the dust off the old slugs. The units are handled in one way or another. I don’t think it is any easier to express or apply than using g.c.